C.P - S.I
[p(1-r/100)^n-p ]-[(P*R*N)/100] = 96.
Where,
p=1500, n=2, R=?, C.P and S.I difference is 96.
[15000(1-r/100)^2-15000 ]-[(1500*R*2)/100] = 96 ...(1).
Now, 15000 common in above so take it out,
15000[1(1-r/100)^2 - 1 ]-[(1*R*2)/100] = 96 ...(2).
Take L.C.M. we get,
15000[(100 + R)^2 - 10000 - (200 x R)/10000] = 96 ...(3).
Where (100 + R)^2 is like (a + b)^2 = (a^2 + b^2 + 2*a*b).
(100^2 + R^2 + 2*100*R) = (10000 + R^2 + 200R).
Sub (10000 + R^2 + 200R) in eqn(3) we get,
15000[ (10000 + R^2 + 200R) - 10000 - (200 x R)/10000] = 96.
15000[ (10000 + R^2 + 200R - 10000 - 200R) /10000] = 96.
Now 10000 and 200R is cancelled, remaining.
15000[ R^2 /10000] = 96.
[15000R^2/10000] = 96.
[15R^2/10] = 96.
divide by 5 we get,
[3R^2/2] = 96.
Now keep the R^2 in left hand side and move 3/2 to right side
R^2 = 96(2/3) // 96/3 = 32.
R^2 = 32*2.
R^2 = 64 // square root of 64 is 8.
R = 8%.
S.I. = Rs. (15000×252×2×1100) =Rs. 3750C.I. = Rs. [15000(1+252×100 )2−15000]=Rs. (15000×98×98−15000)=Rs. (18948.375−15000)=Rs. 3984.375Difference = Rs. (3984.375−3750) =Rs. 234.375
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Jump to
- Compound Interest Exercise 14.1
- Compound Interest Exercise 14.2
- Compound Interest Exercise 14.3
- Compound Interest Exercise 14.4
- Compound Interest Exercise 14.5
- Rational Numbers
- Powers
- Squares and Square Roots
- Cube and Cube Roots
- Playing with Numbers
- Algebraic Expressions and Identities
- Factorization
- Division of Algebraic Expressions
- Linear Equation in One Variable
- Direct and Inverse Variations
- Time and Work
- Percentage
- Profit Loss Discount and Value Added Tax
- Compound Interest
- Understanding Shapes Polygons
- Understanding Shapes Quadrilaterals
- Understanding Shapes Special Types Quadrilaterals
- Practical Goemetry
- Visualising Shapes
- Area of Trapezium and Polygon
- Volume Surface Area Cuboid Cube
- Surface Area and Volume of Right Circular Cylinder
- Classification And Tabulation Of Data
- Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
- Pictorial Representation Of Data As Pie Charts Or Circle Graphs
- Data Handling Probability
- Introduction To Graphs
RD Sharma Solutions Class 8 Mathematics Solutions for Compound Interest Exercise 14.2 in Chapter 14 - Compound Interest
Question 36 Compound Interest Exercise 14.2
The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs. 360. Find the sum.
Answer:
Given,
Time = 2 years
Rate = 7.5 % per annum
Let principal = Rs P
Compound Interest (CI) – Simple Interest (SI) = Rs 360
C.I – S.I = Rs 360
By using the formula,
P [(1 + R/100)^n - 1] – (PTR)/100 = 360
P [(1 + 7.5/100)^2 - 1] – (P(2)(7.5))/100 = 360
P[249/1600] – (3P)/20 = 360
249/1600P – 3/20P = 360
(249P-240P)/1600 = 360
9P = 360 × 1600
P = 576000/9
= 64000
∴ The sum is Rs 64000
Video transcript
hello everybody welcome to leader learning my name is rajna chaudhary and we have to write this statement in the equation form it is written that write equation for the statements for these statements so statement is one fourth of a number x minus g minus four gives four so one fourth of a number x would be one fourth of x that mean the value of this part is 1 by 4 of x then we have to minus 4 from it so let's minus 4 from it so minus 4 and gives gives means is equal to 4 so this is the equation for the statement we can write it like that at the place of off we can write multiply then minus 4 is equal to 4. we can also write it like x upon 4 minus 4 is equal to 4. so this is the form of equation for the statement i hope you understand the method see you in my next video don't forget to like comment and subscribe leader learning channel thank you for watching
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