C.P - S.I Where, Show
[15000(1-r/100)^2-15000 ]-[(1500*R*2)/100] = 96 ...(1). Now, 15000 common in above so take it out, 15000[1(1-r/100)^2 - 1 ]-[(1*R*2)/100] = 96 ...(2). Take L.C.M. we get, 15000[(100 + R)^2 - 10000 - (200 x R)/10000] = 96 ...(3). Where (100 + R)^2 is like (a + b)^2 = (a^2 + b^2 + 2*a*b). (100^2 + R^2 + 2*100*R) = (10000 + R^2 + 200R). Sub (10000 + R^2 + 200R) in eqn(3) we get, 15000[ (10000 + R^2 + 200R) - 10000 - (200 x R)/10000] = 96. 15000[ (10000 + R^2 + 200R - 10000 - 200R) /10000] = 96. Now 10000 and 200R is cancelled, remaining. 15000[ R^2 /10000] = 96. [15000R^2/10000] = 96. [15R^2/10] = 96. divide by 5 we get, [3R^2/2] = 96. Now keep the R^2 in left hand side and move 3/2 to right side R^2 = 96(2/3) // 96/3 = 32. R^2 = 32*2. R^2 = 64 // square root of 64 is 8. R = 8%. S.I. = Rs. (15000×252×2×1100) =Rs. 3750C.I. = Rs. [15000(1+252×100 )2−15000]=Rs. (15000×98×98−15000)=Rs. (18948.375−15000)=Rs. 3984.375Difference = Rs. (3984.375−3750) =Rs. 234.375 Best Selling Hand Written NotesWe are selling best-handwritten notes at a cheap price in Study91 which are follows: Video Class TutorialStudy 91 provide video class tutorials for every aspirants for their exams by their experts. We provide the Best Online Solution with Innovative Contents which is increase your Learning Skills. quick linkscontact us
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RD Sharma Solutions Class 8 Mathematics Solutions for Compound Interest Exercise 14.2 in Chapter 14 - Compound InterestQuestion 36 Compound Interest Exercise 14.2 The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs. 360. Find the sum. Answer: Given, Time = 2 years Rate = 7.5 % per annum Let principal = Rs P Compound Interest (CI) – Simple Interest (SI) = Rs 360 C.I – S.I = Rs 360 By using the formula, P [(1 + R/100)^n - 1] – (PTR)/100 = 360 P [(1 + 7.5/100)^2 - 1] – (P(2)(7.5))/100 = 360 P[249/1600] – (3P)/20 = 360 249/1600P – 3/20P = 360 (249P-240P)/1600 = 360 9P = 360 × 1600 P = 576000/9 = 64000 ∴ The sum is Rs 64000
Video transcript hello everybody welcome to leader learning my name is rajna chaudhary and we have to write this statement in the equation form it is written that write equation for the statements for these statements so statement is one fourth of a number x minus g minus four gives four so one fourth of a number x would be one fourth of x that mean the value of this part is 1 by 4 of x then we have to minus 4 from it so let's minus 4 from it so minus 4 and gives gives means is equal to 4 so this is the equation for the statement we can write it like that at the place of off we can write multiply then minus 4 is equal to 4. we can also write it like x upon 4 minus 4 is equal to 4. so this is the form of equation for the statement i hope you understand the method see you in my next video don't forget to like comment and subscribe leader learning channel thank you for watching Was This helpful?
What will be the difference between S.I and C.I on a sum of 15000 for 2 years?The difference between C.I and S.I on the amount of Rs. 15000 for 2 years is Rs. 96 .
What is the difference in simple interest and compound interest on 15000 for 2 years at 6% per annum compounded annually?Q10. The difference between the simple interest and the compound interest on a certain sum of money for 2 years at the rate of 6% per annum is Rs. 28.80.
What will be the compound interest on 15000 for 2 years at 12.5% per annum?Therefore, compound interest is 3150 Rs.
At what rate difference between C.I and S.I on a sum 1200 is 12 in two years?Detailed Solution
Difference between C.I. and S.I. in two years is 12. ∴ Required rate is 10%.
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