At what rate percent CI does a sum of money become 9 4 times itself in 2 years?

  1. \(69 \frac{1}{2} \%\)
  2. \(67 \frac{1}{2} \%\)
  3. \(62 \frac{1}{2} \%\)
  4. \(61 \frac{1}{2} \%\)

Answer (Detailed Solution Below)

Option 3 : \(62 \frac{1}{2} \%\)

Free

150 Questions 150 Marks 150 Mins

Given:

n = 9/4

Time = 2 years

Formula used:

(n – 1)/T × 100

Calculation:

(n – 1)/T × 100

⇒ (9/4 – 1)/2 × 100

⇒ (5/4)/2 × 100

⇒ 5/8 × 100

⇒ 125/2

⇒ \(62 \frac{1}{2} \%\)

∴ The rate of interest is \(62 \frac{1}{2} \%\)

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If a certain sum of money becomes 9 times itself in 2 years. Find the rate of compound interest?

  1. 50%
  2. 100%
  3. 200%
  4. 80%

Answer (Detailed Solution Below)

Option 3 : 200%

Free

CT 1: Growth and Development - 1

10 Questions 10 Marks 10 Mins

Given:

The sum becomes 9 times in 2 years.

Formula used:

A = P(1 + r/100)t

Calculation:

Let the principal be ‘P’.

⇒ A = P(1 +  r/100)t

⇒ 9P = P(1 + r/100)2

⇒ 9 = (1 + r/100)2

⇒ √9 = 1 + r/100

⇒ 3 = 1 + r/100

⇒ 300 = 100 + r

⇒ r = 200%

 The rate of interest is 200%.

⇒ √1 = √9

⇒ 1 = 3

⇒ 2/1 × 100

⇒ 200% 

 The rate of interest is 200%.

Last updated on Nov 24, 2022

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asked Feb 27 in Aptitude by Vedantk (30.0k points)
closed Mar 2 by Vedantk

Find the rate of interest at which, a sum of money becomes 9/4 times in 2 years.
1. \(69 \frac{1}{2} \%\)
2. \(67 \frac{1}{2} \%\)
3. \(62 \frac{1}{2} \%\)
4. \(61 \frac{1}{2} \%\)

  • quantitative-aptitude
  • interest

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1 Answer

0 votes

answered Feb 27 by KaifGoriya (30.0k points)
selected Feb 27 by Vedantk

Best answer

Correct Answer - Option 3 : \(62 \frac{1}{2} \%\)

Given:

n = 9/4

Time = 2 years

Formula used:

(n – 1)/T × 100

Calculation:

(n – 1)/T × 100

⇒ (9/4 – 1)/2 × 100

⇒ (5/4)/2 × 100

⇒ 5/8 × 100

⇒ 125/2

⇒ \(62 \frac{1}{2} \%\)

∴ The rate of interest is \(62 \frac{1}{2} \%\)

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